3.169 \(\int \frac {\sec ^{\frac {7}{2}}(c+d x)}{(b \sec (c+d x))^{3/2}} \, dx\)

Optimal. Leaf size=35 \[ \frac {\sin (c+d x) \sec ^{\frac {3}{2}}(c+d x)}{b d \sqrt {b \sec (c+d x)}} \]

[Out]

sec(d*x+c)^(3/2)*sin(d*x+c)/b/d/(b*sec(d*x+c))^(1/2)

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Rubi [A]  time = 0.01, antiderivative size = 35, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.130, Rules used = {17, 3767, 8} \[ \frac {\sin (c+d x) \sec ^{\frac {3}{2}}(c+d x)}{b d \sqrt {b \sec (c+d x)}} \]

Antiderivative was successfully verified.

[In]

Int[Sec[c + d*x]^(7/2)/(b*Sec[c + d*x])^(3/2),x]

[Out]

(Sec[c + d*x]^(3/2)*Sin[c + d*x])/(b*d*Sqrt[b*Sec[c + d*x]])

Rule 8

Int[a_, x_Symbol] :> Simp[a*x, x] /; FreeQ[a, x]

Rule 17

Int[(u_.)*((a_.)*(v_))^(m_)*((b_.)*(v_))^(n_), x_Symbol] :> Dist[(a^(m + 1/2)*b^(n - 1/2)*Sqrt[b*v])/Sqrt[a*v]
, Int[u*v^(m + n), x], x] /; FreeQ[{a, b, m}, x] &&  !IntegerQ[m] && IGtQ[n + 1/2, 0] && IntegerQ[m + n]

Rule 3767

Int[csc[(c_.) + (d_.)*(x_)]^(n_), x_Symbol] :> -Dist[d^(-1), Subst[Int[ExpandIntegrand[(1 + x^2)^(n/2 - 1), x]
, x], x, Cot[c + d*x]], x] /; FreeQ[{c, d}, x] && IGtQ[n/2, 0]

Rubi steps

\begin {align*} \int \frac {\sec ^{\frac {7}{2}}(c+d x)}{(b \sec (c+d x))^{3/2}} \, dx &=\frac {\sqrt {\sec (c+d x)} \int \sec ^2(c+d x) \, dx}{b \sqrt {b \sec (c+d x)}}\\ &=-\frac {\sqrt {\sec (c+d x)} \operatorname {Subst}(\int 1 \, dx,x,-\tan (c+d x))}{b d \sqrt {b \sec (c+d x)}}\\ &=\frac {\sec ^{\frac {3}{2}}(c+d x) \sin (c+d x)}{b d \sqrt {b \sec (c+d x)}}\\ \end {align*}

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Mathematica [A]  time = 0.04, size = 32, normalized size = 0.91 \[ \frac {\sin (c+d x) \sec ^{\frac {5}{2}}(c+d x)}{d (b \sec (c+d x))^{3/2}} \]

Antiderivative was successfully verified.

[In]

Integrate[Sec[c + d*x]^(7/2)/(b*Sec[c + d*x])^(3/2),x]

[Out]

(Sec[c + d*x]^(5/2)*Sin[c + d*x])/(d*(b*Sec[c + d*x])^(3/2))

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fricas [A]  time = 0.68, size = 33, normalized size = 0.94 \[ \frac {\sqrt {\frac {b}{\cos \left (d x + c\right )}} \sin \left (d x + c\right )}{b^{2} d \sqrt {\cos \left (d x + c\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sec(d*x+c)^(7/2)/(b*sec(d*x+c))^(3/2),x, algorithm="fricas")

[Out]

sqrt(b/cos(d*x + c))*sin(d*x + c)/(b^2*d*sqrt(cos(d*x + c)))

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sec \left (d x + c\right )^{\frac {7}{2}}}{\left (b \sec \left (d x + c\right )\right )^{\frac {3}{2}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sec(d*x+c)^(7/2)/(b*sec(d*x+c))^(3/2),x, algorithm="giac")

[Out]

integrate(sec(d*x + c)^(7/2)/(b*sec(d*x + c))^(3/2), x)

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maple [A]  time = 0.82, size = 39, normalized size = 1.11 \[ \frac {\left (\frac {1}{\cos \left (d x +c \right )}\right )^{\frac {7}{2}} \cos \left (d x +c \right ) \sin \left (d x +c \right )}{d \left (\frac {b}{\cos \left (d x +c \right )}\right )^{\frac {3}{2}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(sec(d*x+c)^(7/2)/(b*sec(d*x+c))^(3/2),x)

[Out]

1/d*(1/cos(d*x+c))^(7/2)*cos(d*x+c)*sin(d*x+c)/(b/cos(d*x+c))^(3/2)

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maxima [B]  time = 0.85, size = 67, normalized size = 1.91 \[ \frac {2 \, \sqrt {b} \sin \left (2 \, d x + 2 \, c\right )}{{\left (b^{2} \cos \left (2 \, d x + 2 \, c\right )^{2} + b^{2} \sin \left (2 \, d x + 2 \, c\right )^{2} + 2 \, b^{2} \cos \left (2 \, d x + 2 \, c\right ) + b^{2}\right )} d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sec(d*x+c)^(7/2)/(b*sec(d*x+c))^(3/2),x, algorithm="maxima")

[Out]

2*sqrt(b)*sin(2*d*x + 2*c)/((b^2*cos(2*d*x + 2*c)^2 + b^2*sin(2*d*x + 2*c)^2 + 2*b^2*cos(2*d*x + 2*c) + b^2)*d
)

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mupad [B]  time = 0.27, size = 51, normalized size = 1.46 \[ \frac {\left (\cos \left (d\,x\right )-\sin \left (d\,x\right )\,1{}\mathrm {i}\right )\,\left (\cos \relax (c)-\sin \relax (c)\,1{}\mathrm {i}\right )\,\sqrt {\frac {b}{\cos \left (c+d\,x\right )}}\,\sqrt {\frac {1}{\cos \left (c+d\,x\right )}}\,1{}\mathrm {i}}{b^2\,d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1/cos(c + d*x))^(7/2)/(b/cos(c + d*x))^(3/2),x)

[Out]

((cos(d*x) - sin(d*x)*1i)*(cos(c) - sin(c)*1i)*(b/cos(c + d*x))^(1/2)*(1/cos(c + d*x))^(1/2)*1i)/(b^2*d)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sec(d*x+c)**(7/2)/(b*sec(d*x+c))**(3/2),x)

[Out]

Timed out

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